Question 1
For the linear function f, f(0) = 1 and f(1) = 6. What is the value of f(2)?
- A.
10
- B.
11
- C.
12
- D.
16
Answer: B. 11
The slope is (6 - (1))/(1 - 0) = 5, so f(x) = 5x + 1. Then f(2) = 5(2) + (1) = 11.
SAT · ACT · MCATGoal-based prepLive 1:1 + GoalGap AI
SAT · Math · Algebra
Linear functions is part of Algebra in the SAT Math section. The questions below are written in the style of the real test, each with the answer and a worked explanation.
Question types you will see here include meaning of slope and intercept, equation from two points, rate of change from a table and parallel and perpendicular lines.
Common traps: swapping slope and intercept; missing the units of the rate; treating the intercept as a rate.
Question 1
For the linear function f, f(0) = 1 and f(1) = 6. What is the value of f(2)?
10
11
12
16
Answer: B. 11
The slope is (6 - (1))/(1 - 0) = 5, so f(x) = 5x + 1. Then f(2) = 5(2) + (1) = 11.
Question 2
| Hours since bidding opened | Total raised ($) |
|---|---|
| 0 | 400 |
| 2 | 1,000 |
| 5 | 2,200 |
What was the average rate of change of the total raised, in dollars per hour, from hour 2 to hour 5?
400
440
500
1200
Answer: A. 400
Average rate of change = (2,200 − 1,000)/(5 − 2) = 1,200/3 = 400 dollars per hour. B divides the hour-5 total by 5, using an end value only; C divides the hour-2 total by 2, using the wrong interval; D is the change in dollars and was never divided by the 3 hours.
Question 3
Gym A charges a $25 joining fee plus $8 per visit. Gym B charges a $10 joining fee plus $11 per visit. For how many visits is the total cost the same at both gyms?
3
5
11.7
15
Answer: B. 5
B is correct: 25 + 8v = 10 + 11v gives 15 = 3v, so v = 5 visits (both cost $65). A is the difference in the per-visit prices. C divides the sum of the fees by the price difference. D is the difference in the joining fees.
Question 4
A cooking class charges a total fee F, in dollars, that is a linear function of the number of attendees n. For 2 attendees the fee is $190, and for 6 attendees it is $390. For how many attendees is the fee $840?
Enter your own answer.
Answer: 15
The slope is (390 − 190)/(6 − 2) = 50 dollars per attendee, and the intercept is 190 − 2(50) = 90, so F(n) = 50n + 90. Setting 50n + 90 = 840 gives n = 15. Evaluating F(840) instead of solving for n is the main trap.
Question 5
The line ℓ has the equation y = −(2/3)x + 5. The line m is perpendicular to ℓ and passes through the point (6, 1). What is the y-intercept of line m?
-8
-3
5
10
Answer: A. -8
A perpendicular slope is the negative reciprocal, 3/2. Then 1 = (3/2)(6) + b gives b = −8 (A). Choice B uses 2/3, changing only the sign; C uses the parallel slope −2/3 (b = 5); D uses −3/2, taking only the reciprocal.
A few questions show the style. The free scan shows which SAT skills cost you the most points, then builds a plan around them.